Compounds A and B,both were treated with NaOH | vedclass

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(A) The reaction involves a retro-aldol cleavage followed by an intramolecular aldol condensation. $1$. The base $HO^-$ attacks the hydroxyl group of

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Cyclopent$-2-$en$-1-$one

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(A) The reaction involves a retro-aldol cleavage followed by an intramolecular aldol condensation. $1$. The base $HO^-$ attacks the hydroxyl group of the cyclopropane derivative,leading to the opening of the ring via a retro-aldol mechanism to form a linear intermediate,$CH_3-CO-CH_2-CH_2-CHO$. $2$. This linear intermediate then undergoes an intramolecular aldol condensation in the presence of $HO^-$ and heat to form a five-membered ring with a double bond,which is cyclopent$-2-$en$-1-$one. $3$. Thus,the final product $C$ is cyclopent$-2-$en$-1-$one.

Compounds $A$ and $B$,both were treated with $NaOH$,producing a single compound $C$. Identify compound $C$.

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