Compound $A$ $(C_9H_{10}O)$ shows a positive iodoform test. Oxidation of $A$ with $KMnO_4/KOH$ gives acid $B$ $(C_8H_6O_4)$. The anhydride of $B$ is used for the preparation of phenolphthalein. Compound $A$ is:

  • A
    $2-$Methylacetophenone
  • B
    $3-$Methylacetophenone
  • C
    $2-$Ethylbenzaldehyde
  • D
    $4-$Methylacetophenone

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