Compound C_4H_8Cl_2 (A) on hydrolysis gives a | vedclass

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(D) Compound $(B)$ $(C_4H_8O)$ reacts with hydroxylamine $(NH_2OH)$ to form an oxime,which indicates that it is a carbonyl compound.Since it does not

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$2,2-$Dichlorobutane and butanone

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(D) Compound $(B)$ $(C_4H_8O)$ reacts with hydroxylamine $(NH_2OH)$ to form an oxime,which indicates that it is a carbonyl compound.Since it does not give a Tollen's test,it must be a ketone.The only $4-$carbon ketone is butanone $(CH_3-CO-CH_2-CH_3)$.Hydrolysis of a gem-dichloride $(A)$ gives a ketone,so $(A)$ must be $2,2-$dichlorobutane $(CH_3-CCl_2-CH_2-CH_3)$.$CH_3-CCl_2-CH_2-CH_3 \xrightarrow{H_2O} CH_3-CO-CH_2-CH_3$

Compound $C_4H_8Cl_2$ $(A)$ on hydrolysis gives a compound $C_4H_8O$ $(B)$ which reacts with hydroxylamine and does not give any test with Tollen's reagent. What are $(A)$ and $(B)$?

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