Compound A reacts with PCl_5 to give B,which | vedclass

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(D) The reaction sequence is as follows:$1$. $C_2H_5OH$ $(A) + PCl_5 	o C_2H_5Cl$ $(B) + POCl_3 + HCl$$2$. $C_2H_5Cl$ $(B) + KCN 	o C_2H_5CN + KCl$$

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$C_2H_5OH$ and $C_2H_5Cl$

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(D) The reaction sequence is as follows:$1$. $C_2H_5OH$ $(A) + PCl_5 	o C_2H_5Cl$ $(B) + POCl_3 + HCl$$2$. $C_2H_5Cl$ $(B) + KCN 	o C_2H_5CN + KCl$$3$. $C_2H_5CN + 2H_2O \xrightarrow{H^+} C_2H_5COOH$ (Propionic acid)Since the final product is propionic acid $(C_2H_5COOH)$,which contains $3$ carbon atoms,the starting material $A$ must be ethanol $(C_2H_5OH)$ and $B$ must be ethyl chloride $(C_2H_5Cl)$.

Compound $A$ reacts with $PCl_5$ to give $B$,which on treatment with $KCN$ followed by hydrolysis gives propionic acid. What are $A$ and $B$ respectively?

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