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(B) The reaction of $2$-bromo-$3$-methylbutane with $Mg$ in $Et_2O$ forms a Grignard reagent,$3$-methylbutylmagnesium bromide $(CH_3-CH(CH_3)-CH(MgBr)

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$2$-Deuterio-$3$-methylbutane,Chiral

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(B) The reaction of $2$-bromo-$3$-methylbutane with $Mg$ in $Et_2O$ forms a Grignard reagent,$3$-methylbutylmagnesium bromide $(CH_3-CH(CH_3)-CH(MgBr)-CH_3)$.When this Grignard reagent is treated with $D_2O$,the $MgBr$ group is replaced by a deuterium atom $(D)$,resulting in $2$-deuterio-$3$-methylbutane $(CH_3-CH(CH_3)-CH(D)-CH_3)$.In $2$-deuterio-$3$-methylbutane,the carbon atom at position $2$ is bonded to four different groups: a hydrogen atom $(H)$,a deuterium atom $(D)$,a methyl group $(-CH_3)$,and an isopropyl group $(-CH(CH_3)_2)$.Since the carbon at position $2$ is bonded to four distinct groups,it is a chiral center,making the molecule chiral.

Compound $A$ undergoes the following sequence of reactions to give compound $B$. The correct structure and chirality of compound $B$ is:
[where $Et$ is $-C_2H_5$]

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Compound $A$ undergoes the following sequence of reactions to give compound $B$. The correct structure and chirality of compound $B$ is:[where $Et$ is $-C_2H_5$]