Compound P is neutral. Q gives effervescence | vedclass

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(B) Compound $P$ has the molecular formula $C_{14}H_{13}ON$. Upon hydrolysis with $HCl$ and $\Delta$,it yields a carboxylic acid $(Q)$ and an amine $(

Vedclass · Accepted Answer

$N$-phenyl$-4-$methylbenzamide

Vedclass · Answer

(B) Compound $P$ has the molecular formula $C_{14}H_{13}ON$. Upon hydrolysis with $HCl$ and $\Delta$,it yields a carboxylic acid $(Q)$ and an amine $(R)$. $Q$ gives effervescence with $NaHCO_3$,indicating it is a carboxylic acid. $R$ reacts with Hinsberg's reagent $(PhSO_2Cl)$ to form a product that is soluble in $NaOH$,which confirms that $R$ is a primary amine ($1^{\circ}$ amine). Based on the molecular formula $C_{14}H_{13}ON$,the compound $P$ is $N$-phenyl$-4-$methylbenzamide $(CH_3-C_6H_4-CONH-C_6H_5)$. Hydrolysis of $N$-phenyl$-4-$methylbenzamide gives $4-$methylbenzoic acid $(Q)$ and aniline $(R)$. Aniline $(R)$ reacts with Hinsberg's reagent to form $N$-phenylbenzenesulfonamide,which is soluble in $NaOH$ due to the acidic hydrogen on the nitrogen atom.

List-$I$ (Functional group)	List-$II$ (Functional group reagent)
$(a)$ Aliphatic Alcohol	$(i)$ Neutral ferric chloride test
$(b)$ $C_6H_5NH_2$	(ii) Azo dye test
$(c)$ $CH_3CH_2CHO$	(iii) Ceric ammonium nitrate test
$(d)$ Phenol	(iv) Tollen’s reagent test

Compound $P$ is neutral. $Q$ gives effervescence with $NaHCO_3$ while $R$ reacts with Hinsberg's reagent to give a solid soluble in $NaOH$. Compound $P$ is:

Similar Questions

Identify the incorrect statement based on the following reaction sequence:
$C_6H_5N_2^+Cl^-$ $\xrightarrow{H_3PO_2/H_2O} A$ $\xrightarrow{SO_3} B$ $\xrightarrow{PCl_5} C$ $\xrightarrow{EtNH_2} D$

In the carbylamine test for primary amines,the resulting foul-smelling product is:

Which of the following amines will give the carbylamine test?

Which of the following does $NOT$ give carbylamine test?

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