Compound A from the following reaction sequen | vedclass

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(D) The reaction sequence is as follows:$1$. $A$ is $Aniline$ $(C_6H_5NH_2)$.$2$. When $Aniline$ reacts with $Br_2$ in water (or $Br_2/CS_2$ at low te

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Aniline

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(D) The reaction sequence is as follows:$1$. $A$ is $Aniline$ $(C_6H_5NH_2)$.$2$. When $Aniline$ reacts with $Br_2$ in water (or $Br_2/CS_2$ at low temperature),it undergoes electrophilic substitution to form $2,4,6-tribromoaniline$ (Compound $B$).$3$. $2,4,6-tribromoaniline$ reacts with $NaNO_2/HCl$ at $0-5^{\circ}C$ to form the diazonium salt,$2,4,6-tribromobenzenediazonium$ chloride (Compound $C$).$4$. Finally,reduction of the diazonium salt with $H_3PO_2$ and water removes the $-N_2^+Cl^-$ group,yielding $1,3,5-tribromobenzene$.Thus,compound $A$ is $Aniline$.

Compound $A$ from the following reaction sequence is:

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