Compound A (C_3H_6O) undergoes the following | vedclass

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Question

(A) The compound $A$ is $CH_3COCH_3$ (acetone),which has the molecular formula $C_3H_6O$. $1$. Reaction with $I_2/NaOH$ (Iodoform test): Acetone react

Vedclass · Accepted Answer

$A = CH_3COCH_3, B = CHI_3, C = CH_3CH_2CH_3$

Vedclass · Answer

(A) The compound $A$ is $CH_3COCH_3$ (acetone),which has the molecular formula $C_3H_6O$. $1$. Reaction with $I_2/NaOH$ (Iodoform test): Acetone reacts with $I_2$ in the presence of $NaOH$ to give a yellow precipitate of iodoform $(CHI_3)$. $CH_3COCH_3 + 3I_2 + 4NaOH \rightarrow CHI_3 + CH_3COONa + 3NaI + 3H_2O$. Here,$B$ is $CHI_3$. $2$. Reaction with $Zn-Hg/HCl$ (Clemmensen reduction): Acetone undergoes reduction to form propane $(CH_3CH_2CH_3)$. $CH_3COCH_3 \xrightarrow{Zn-Hg/HCl} CH_3CH_2CH_3$. Here,$C$ is $CH_3CH_2CH_3$.

Compound $A$ $(C_3H_6O)$ undergoes the following reactions to form $B$ and $C$. Identify $A, B$ and $C$.

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