Compound $CH_3-CO-CH_2-OH$ reduces:

  • A
    Tollen's reagent
  • B
    $NaOH / I_2$ solution
  • C
    Fehling solution
  • D
    All of these

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Acetoacetic ester behaves as

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Reductive amination of $A$ forms :
$A$ :

Metaformaldehyde is:

The starting material is $CH_3COCH_2CHO$. The reaction sequence is:
$CH_3COCH_2CHO$ $\xrightarrow[{(ii)LiAlH_4}]{{(i)ethylene\,glycol/dry\,HCl}} A$ $\xrightarrow[\Delta ]{H_3O^{+}} B$
What will be $B$?

Assertion : Benzaldehyde is more reactive than ethanol towards nucleophilic attack.
Reason : The overall effect of $-I$ and $+R$ effect of phenyl group decreases the electron density on the carbon atom of $>C=O$ group in benzaldehyde.

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