Compounds having the highest oxidation state | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The oxidation states of chlorine in the given compounds are: $1$. In $HOCl$,$O.S. = +1$ $2$. In $HClO_2$,$O.S. = +3$ $3$. In $HClO_4$,$O.S. = +7$

Vedclass · Accepted Answer

None

Vedclass · Answer

(D) The oxidation states of chlorine in the given compounds are: $1$. In $HOCl$,$O.S. = +1$ $2$. In $HClO_2$,$O.S. = +3$ $3$. In $HClO_4$,$O.S. = +7$ For chlorine oxyacids,the acidic strength increases with the increase in oxidation state. $HClO_4$ $(+7)$ is a strong acid,$HClO_2$ $(+3)$ is an intermediate acid,and $HOCl$ $(+1)$ is the weakest acid. None of these act as amphoteric in the context of these specific oxyacids,as they all primarily exhibit acidic character.

Compound	Oxidation number
$1$. $C_6H_{12}O_6$ (Carbon)	$a$. $+1$
$2$. $CCl_4$ (Carbon)	$b$. $0$
$3$. $NH_4Cl$ (Nitrogen)	$c$. $+4$
$4$. $Ba(H_2PO_2)_2$ (Phosphorus)	$d$. $-3$

Compounds having the highest oxidation state of the central atom act as acids,the lowest ones act as bases,and intermediate oxidation states act as amphoteric. Which one of the following is amphoteric?

Similar Questions

What is the formula of the manganate ion?

Oxidation number of oxygen in ozone $(O_3)$ is

Chlorine is in $+1$ oxidation state in

Match the following compounds with the oxidation number of the central atom (or specific atom in question):

Compound Oxidation number

$1$. $C_6H_{12}O_6$ (Carbon) $a$. $+1$

$2$. $CCl_4$ (Carbon) $b$. $0$

$3$. $NH_4Cl$ (Nitrogen) $c$. $+4$

$4$. $Ba(H_2PO_2)_2$ (Phosphorus) $d$. $-3$

The oxidation number of $Cr$ in $K_3CrO_8$ is $+5$. How many peroxy linkages are present in this molecule?

Vedclass Test Series

Exam Paper Generator

Online Exam Module