CompoundTotal stereoisomersA. [Co(en)_2Cl_2]^ | vedclass

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(B) . $[Co(en)_2Cl_2]^+$: This complex shows cis-trans isomerism. The cis-isomer is optically active ($2$ enantiomers) and the trans-isomer is optical

Vedclass · Accepted Answer

$A-Q, B-P, C-P, D-P$

Vedclass · Answer

(B) . $[Co(en)_2Cl_2]^+$: This complex shows cis-trans isomerism. The cis-isomer is optically active ($2$ enantiomers) and the trans-isomer is optically inactive. Total stereoisomers = $2 + 1 = 3$ $(Q)$.$B$. $[Co(en)_3]Cl_3$: This complex has $2$ optical isomers (enantiomers) and no geometric isomers. Total stereoisomers = $2$ $(P)$.$C$. $[Pt(NH_3)_2Cl_2]$: This is a square planar complex showing cis-trans isomerism. Both are optically inactive. Total stereoisomers = $2$ $(P)$.$D$. $[Pt(NH_3)_3Cl_3]^+$: This is an octahedral complex showing facial (fac) and meridional (mer) isomers. Both are optically inactive. Total stereoisomers = $2$ $(P)$.Therefore,the correct matching is $A-Q, B-P, C-P, D-P$.

List-$I$ (Complex)	List-$II$ (Type of isomerism)
$A$. $[Co(NH_3)_5(NO_2)]Cl_2$	$I$. Solvate isomerism
$B$. $[Co(NH_3)_5(SO_4)]Br$	$II$. Linkage isomerism
$C$. $[Co(NH_3)_6][Cr(CN)_6]$	$III$. Ionization isomerism
$D$. $[Co(H_2O)_6]Cl_3$	$IV$. Coordination isomerism

Compound Total stereoisomers
$A$. $[Co(en)_2Cl_2]^+$ $P$. $2$
$B$. $[Co(en)_3]Cl_3$ $Q$. $3$
$C$. $[Pt(NH_3)_2Cl_2]$ $R$. $4$
$D$. $[Pt(NH_3)_3Cl_3]^+$ $S$. $5$

Match the compounds with their total number of stereoisomers and select the correct code:

Similar Questions

$[Co(NH_3)Cl(en)_2]^{2+}$ shows two geometrical isomers,$cis$ and $trans$. Which of the following statements is correct?

The total possible coordination isomers for the following compounds respectively are :
$[Co(en)_3] [Cr(C_2O_4)_3]$
$[Cu(NH_3)_4] [CuCl_4]$
$[Ni(en)_3] [Co(NO_2)_6]$

Total number of relatively more stable isomer$(s)$ possible for octahedral complex $[Cu(en)_2(SCN)_2]$ will be $.........$

What are the complex ions $[Co(NH_3)_5(NO_2)]^{2+}$ and $[Co(NH_3)_5(ONO)]^{2+}$ called?

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Compound	Total stereoisomers
$A$. $[Co(en)_2Cl_2]^+$	$P$. $2$
$B$. $[Co(en)_3]Cl_3$	$Q$. $3$
$C$. $[Pt(NH_3)_2Cl_2]$	$R$. $4$
$D$. $[Pt(NH_3)_3Cl_3]^+$	$S$. $5$

CompoundTotal stereoisomers$A$. $[Co(en)_2Cl_2]^+$$P$. $2$$B$. $[Co(en)_3]Cl_3$$Q$. $3$$C$. $[Pt(NH_3)_2Cl_2]$$R$. $4$$D$. $[Pt(NH_3)_3Cl_3]^+$$S$. $5$Match the compounds with their total number of stereoisomers and select the correct code: