(C) Given that the concentration of $HNO_3$ is $75 \% \ w/w$. This means $100 \ g$ of the solution contains $75 \ g$ of $HNO_3$. The density of the so

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(C) Given that the concentration of $HNO_3$ is $75 \% \ w/w$. This means $100 \ g$ of the solution contains $75 \ g$ of $HNO_3$. The density of the solution is $d = 1.25 \ g/mL$. The volume of $100 \ g$ of the solution is $V = \frac{\text{mass}}{\text{density}} = \frac{100 \ g}{1.25 \ g/mL} = 80 \ mL$. Thus,$75 \ g$ of $HNO_3$ is present in $80 \ mL$ of the solution. Therefore,the volume of the solution containing $30 \ g$ of $HNO_3$ is $\frac{80 \ mL}{75 \ g} \times 30 \ g = 32 \ mL$.

Class 11 Chemistry Some Basic Concepts of Chemistry Chemical stoichiometry

Medium

Concentrated nitric acid is labelled as $75 \%$ by mass. The volume in $mL$ of the solution which contains $30 \ g$ of nitric acid is $.............$ Given : Density of nitric acid solution is $1.25 \ g / mL$

JEE MAIN 2025 All JEE MAIN

A
$45$
B
$55$
C
$32$
D
$40$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Chemistry Questions

Chapter

Some Basic Concepts of Chemistry

Subtopic

Chemical stoichiometry

Previous Year

JEE MAIN 2025 Paper All JEE MAIN years →

Combustion of glucose $(C_6H_{12}O_6)$ produces $CO_2$ and water. The amount of oxygen (in $g$) required for the complete combustion of $900 \ g$ of glucose is:
[Molar mass of glucose in $g \ mol^{-1} = 180$]

MediumJEE MAIN 2024

View Solution

Volume of air required to completely burn $10 \ L$ of $C_2H_4$ is ................ $L$ (assume all volumes are measured at the same temperature and pressure,and air contains $20\%$ oxygen by volume).

Medium

View Solution

The formula of a gaseous hydrocarbon which requires $6$ times of its own volume of $O_{2}$ for complete oxidation and produces $4$ times its own volume of $CO_{2}$ is $C_{x}H_{y}$. The value of $y$ is $......$ .

DifficultJEE MAIN 2021

View Solution

$x$ grams of calcium carbonate was completely burnt in air. The weight of the solid residue formed is $28 \,g$. What is the value of $x$ (in grams)?

DifficultAP EAMCET 2005

View Solution

What will be the volume of $CO_2$ at $S.T.P.$ obtained by heating $9.85 \ g$ of $BaCO_3$? (Atomic mass of $Ba = 137$)

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

Concentrated nitric acid is labelled as $75 \%$ by mass. The volume in $mL$ of the solution which contains $30 \ g$ of nitric acid is $.............$ Given : Density of nitric acid solution is $1.25 \ g / mL$

Similar Questions

Combustion of glucose $(C_6H_{12}O_6)$ produces $CO_2$ and water. The amount of oxygen (in $g$) required for the complete combustion of $900 \ g$ of glucose is:[Molar mass of glucose in $g \ mol^{-1} = 180$]

Volume of air required to completely burn $10 \ L$ of $C_2H_4$ is ................ $L$ (assume all volumes are measured at the same temperature and pressure,and air contains $20\%$ oxygen by volume).

The formula of a gaseous hydrocarbon which requires $6$ times of its own volume of $O_{2}$ for complete oxidation and produces $4$ times its own volume of $CO_{2}$ is $C_{x}H_{y}$. The value of $y$ is $......$ .

$x$ grams of calcium carbonate was completely burnt in air. The weight of the solid residue formed is $28 \,g$. What is the value of $x$ (in grams)?

What will be the volume of $CO_2$ at $S.T.P.$ obtained by heating $9.85 \ g$ of $BaCO_3$? (Atomic mass of $Ba = 137$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Combustion of glucose $(C_6H_{12}O_6)$ produces $CO_2$ and water. The amount of oxygen (in $g$) required for the complete combustion of $900 \ g$ of glucose is:
[Molar mass of glucose in $g \ mol^{-1} = 180$]