Conductivity of a conductor is

Calculate the conductivity of $0.02 \ M$ electrolyte solution if its molar conductivity is $407.2 \ \Omega^{-1} \ cm^2 \ mol^{-1}$.

Resistance of a cell containing $0.02 \ M \ KCl$ solution is $164 \ \Omega$. If the cell is filled with $0.05 \ M \ AgNO_3$,the resistance becomes $75.8 \ \Omega$. Calculate the following: [Conductivity of $0.02 \ M \ KCl = 2.768 \times 10^{-3} \ \Omega^{-1} \ cm^{-1}$] $(i)$ Conductivity of $0.05 \ M \ AgNO_3$ (ii) Molar conductivity of $AgNO_3$ solution.

The conductivity of an electrolytic solution decreases on dilution due to

Resistance of a conductivity cell filled with $0.1 \, mol \, L^{-1}$ $KCl$ solution is $100 \, \Omega$. If the resistance of the same cell when filled with $0.02 \, mol \, L^{-1}$ $KCl$ solution is $520 \, \Omega$,calculate the conductivity and molar conductivity of $0.02 \, mol \, L^{-1} \, KCl$ solution. The conductivity of $0.1 \, mol \, L^{-1} \, KCl$ solution is $1.29 \, S / m$.

Equivalent conductivity at infinite dilution for sodium potassium oxalate $[(COO^{-})_{2} Na^{+} K^{+}]$ will be (given molar conductivities of oxalate, $K^{+}$ and $Na^{+}$ ions at infinite dilution are $148.2$, $50.1$, and $73.5 \ S \ cm^{2} \ mol^{-1}$ respectively).