Consider a p-n junction as a capacitor,formed | vedclass

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Question

(A) In an $n-p-n$ transistor,the base-emitter junction is forward-biased,while the collector-base junction is reverse-biased.Capacitance $C$ is given

Vedclass · Accepted Answer

$C_1 > C_2$

Vedclass · Answer

(A) In an $n-p-n$ transistor,the base-emitter junction is forward-biased,while the collector-base junction is reverse-biased.Capacitance $C$ is given by $C = \frac{\epsilon A}{d}$,where $d$ is the width of the depletion layer.For a forward-biased junction (base-emitter),the depletion layer width $d_1$ is very small.For a reverse-biased junction (collector-base),the depletion layer width $d_2$ is significantly larger.Since $C \propto \frac{1}{d}$,a smaller depletion width leads to a larger capacitance.Therefore,$C_1$ (base-emitter capacitance) is greater than $C_2$ (collector-base capacitance).Thus,$C_1 > C_2$.

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