(C) The mass of the trolley is $m_1 = 20 \text{ kg}$ and the mass of the hanging block is $m_2 = 6 \text{ kg}$.The normal force on the trolley is $N =

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(C) The mass of the trolley is $m_1 = 20 \text{ kg}$ and the mass of the hanging block is $m_2 = 6 \text{ kg}$.The normal force on the trolley is $N = m_1 g = 20 \times 10 = 200 \text{ N}$.The kinetic friction force is $f_k = \mu_k N = 0.04 \times 200 = 8 \text{ N}$.The driving force is the weight of the hanging block,$F = m_2 g = 6 \times 10 = 60 \text{ N}$.Applying Newton's second law to the system: $F - f_k = (m_1 + m_2) a$.$60 - 8 = (20 + 6) a$.$52 = 26 a$.$a = \frac{52}{26} = 2 \text{ m/s}^2$.

Class 11 Physics Newton's Laws of Motion and Friction Kinetic Friction and Motion on Rough Horizontal Surface

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Consider a block and trolley system as shown in the figure. If the coefficient of kinetic friction between the trolley and the surface is $0.04$,the acceleration of the system in $m/s^2$ is (Consider that the string is massless and unstretchable and the pulley is also massless and frictionless):

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Newton's Laws of Motion and Friction

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Kinetic Friction and Motion on Rough Horizontal Surface

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Consider a block and trolley system as shown in the figure. If the coefficient of kinetic friction between the trolley and the surface is $0.04$,the acceleration of the system in $m/s^2$ is (Consider that the string is massless and unstretchable and the pulley is also massless and frictionless):

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$A$ small block of mass $m$ is projected horizontally with speed $u$. The coefficient of friction between the block and the plane is given by $\mu = cx$,where $x$ is the displacement of the block on the plane. Find the maximum distance covered by the block.

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