(B) First,convert the speed from $km/h$ to $m/s$: $u = 72 \times \frac{5}{18} = 20 \, m/s$. When the car stops,the final velocity $v = 0$. The retardi

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(B) First,convert the speed from $km/h$ to $m/s$: $u = 72 \times \frac{5}{18} = 20 \, m/s$. When the car stops,the final velocity $v = 0$. The retarding force is the kinetic friction $f_k = \mu_k N = \mu_k mg$. Using Newton's second law,$ma = -f_k = -\mu_k mg$,so the deceleration $a = -\mu_k g$. Using the kinematic equation $v^2 - u^2 = 2as$: $0^2 - (20)^2 = 2(-\mu_k g)s$. $s = \frac{u^2}{2 \mu_k g} = \frac{20^2}{2 \times 0.5 \times 10} = \frac{400}{10} = 40 \, m$.

Class 11 Physics Newton's Laws of Motion and Friction Kinetic Friction and Motion on Rough Horizontal Surface

Medium

Consider a car moving along a straight horizontal road with a speed of $72 \, km/h$. If the coefficient of kinetic friction between the tyres and the road is $0.5$,the shortest distance in which the car can be stopped is ........ $m$. $[g = 10 \, m/s^2]$

AIPMT 1992 All AIPMT

A
$30$
B
$40$
C
$72$
D
$20$

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Class 11

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Chapter

Newton's Laws of Motion and Friction

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Kinetic Friction and Motion on Rough Horizontal Surface

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Consider a car moving along a straight horizontal road with a speed of $72 \, km/h$. If the coefficient of kinetic friction between the tyres and the road is $0.5$,the shortest distance in which the car can be stopped is ........ $m$. $[g = 10 \, m/s^2]$

Similar Questions

$A$ spring-block system is placed on a rough horizontal floor. The block is pulled towards the right to give the spring some elongation and then released. The block will have maximum velocity when:

$A$ $60 \, kg$ mass is dragged on a horizontal surface by a rope for a distance of $2 \, m$. If the coefficient of friction is $\mu = 0.5$,the angle of the rope with the surface is $60^\circ$,and $g = 9.8 \, m/s^2$,then the work done against friction is ........ $J$.

$A$ particle of mass '$m$' at rest on a rough horizontal surface with a coefficient of friction '$\mu$' is given a velocity '$u$'. The average power imparted by friction before it stops is:

$A$ block is projected with speed $20 \,m/s$ on a rough horizontal surface. The coefficient of friction $(\mu)$ between the surfaces varies with time $(t)$ as shown in the figure. The speed of the body at the end of $4 \,s$ will be ............ $m/s$ $(g = 10 \,m/s^2)$.

$A$ cylinder of $10 \, kg$ is sliding on a plane with an initial velocity of $10 \, m/s$. If the coefficient of friction between the surface and the cylinder is $0.5$,then the distance it will cover before stopping is ........ $m$. $(g = 10 \, m/s^2)$

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