Consider a gas of triatomic molecules. The mo | vedclass

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(D) For a non-linear (triangular) rigid molecule,the degrees of freedom $(f)$ are calculated as follows:$1$. Translational degrees of freedom: $3$ (al

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$3$

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(D) For a non-linear (triangular) rigid molecule,the degrees of freedom $(f)$ are calculated as follows:$1$. Translational degrees of freedom: $3$ (along $x, y, z$ axes).$2$. Rotational degrees of freedom: $3$ (about the three principal axes of rotation for a non-linear molecule).Total degrees of freedom $(f)$ = $3 + 3 = 6$.The internal energy $(U)$ of $n$ moles of an ideal gas is given by $U = \frac{f}{2} nRT$.For $n = 1$ mole and $f = 6$:$U = \frac{6}{2} 	imes 1 	imes RT = 3RT$.Thus,the internal energy is $3RT$.

Consider a gas of triatomic molecules. The molecules are assumed to be triangular and made of massless rigid rods whose vertices are occupied by atoms. The internal energy of a mole of the gas at temperature $T$ is $......RT$.

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