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(A) $1$. In the first reaction,aniline reacts with $Br_2$ in water (excess). Due to the strongly activating nature of the $-NH_2$ group,electrophilic

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$2,4,6$-tribromoaniline and $p$-bromoaniline

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(A) $1$. In the first reaction,aniline reacts with $Br_2$ in water (excess). Due to the strongly activating nature of the $-NH_2$ group,electrophilic substitution occurs at all ortho and para positions,yielding $2,4,6$-tribromoaniline as the major product $A$.$2$. In the second reaction,aniline is first acetylated using acetic anhydride to form acetanilide. This protects the $-NH_2$ group and reduces its activating effect. Subsequent bromination with $Br_2$ in $CH_3COOH$ occurs primarily at the para position due to steric hindrance at the ortho positions. Finally,hydrolysis with $HCl$ removes the acetyl group to yield $p$-bromoaniline as the major product $B$.

Consider the above reaction,the product $A$ and product $B$ respectively are ...

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