Consider the acidity of the following carboxy | vedclass

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(B) The acidity of substituted benzoic acids depends on the electronic effects of the substituents.$1$. The $-NO_2$ group is a strong electron-withdra

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$B > C > D > A$

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(B) The acidity of substituted benzoic acids depends on the electronic effects of the substituents.$1$. The $-NO_2$ group is a strong electron-withdrawing group ($-I$ and $-M$ effects),which increases the acidity of benzoic acid compared to $PhCOOH$ $(A)$.$2$. Due to the ortho effect,the ortho-substituted isomer $(B)$ is the most acidic among the nitrobenzoic acids.$3$. For the meta and para isomers,the $-NO_2$ group at the para position $(C)$ exerts both $-I$ and $-M$ effects,whereas at the meta position $(D)$,it exerts only the $-I$ effect. However,the $-M$ effect is stronger at the para position,making $p-NO_2C_6H_4COOH$ more acidic than $m-NO_2C_6H_4COOH$.$4$. Therefore,the correct order of acidity is: $o-NO_2C_6H_4COOH (B) > p-NO_2C_6H_4COOH (C) > m-NO_2C_6H_4COOH (D) > PhCOOH (A)$.Thus,the correct option is $B$.

Consider the acidity of the following carboxylic acids. Which of the following orders is correct?
$A$. $PhCOOH$
$B$. $o-NO_2C_6H_4COOH$
$C$. $p-NO_2C_6H_4COOH$
$D$. $m-NO_2C_6H_4COOH$

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Consider the acidity of the following carboxylic acids. Which of the following orders is correct?$A$. $PhCOOH$$B$. $o-NO_2C_6H_4COOH$$C$. $p-NO_2C_6H_4COOH$$D$. $m-NO_2C_6H_4COOH$