Consider the elements N, P, O, S, Cl and F. T | vedclass

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(C) Metallic character increases down a group and decreases across a period from left to right. Among the given elements ($N$, $P$, $O$, $S$, $Cl$, $F

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$5$ and $7$

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(C) Metallic character increases down a group and decreases across a period from left to right. Among the given elements ($N$, $P$, $O$, $S$, $Cl$, $F$), $P$ (Phosphorus) is the most metallic as it is the furthest to the left and down in the periodic table compared to the others. Its valence shell configuration is $3s^2 3p^3$, so it has $5$ valence electrons.$F$ (Fluorine) is the most electronegative and least metallic element in the list. Its valence shell configuration is $2s^2 2p^5$, so it has $7$ valence electrons.Therefore, the number of valence electrons for the most metallic $(P)$ and least metallic $(F)$ elements are $5$ and $7$ respectively.

Consider the elements $N$, $P$, $O$, $S$, $Cl$ and $F$. The number of valence electrons present in the elements with most and least metallic character from the above list is respectively.

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