Consider the following complex: $[Co(NH_3)_5CO_3]ClO_4$. The coordination number,oxidation number,number of $d-$ electrons,and number of unpaired $d-$ electrons on the metal are respectively:

  • A
    $6, 2, 7, 3$
  • B
    $7, 2, 7, 1$
  • C
    $5, 3, 6, 4$
  • D
    $6, 3, 6, 0$

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Similar Questions

Give the correct sequence of initials $T$ or $F$ for the following statements. Use $T$ if the statement is true and $F$ if it is false.
$(I) \ Co(III)$ is stabilized in the presence of weak field ligands,while $Co(II)$ is stabilized in the presence of strong field ligands.
$(II)$ Four-coordinated complexes of $Pd(II)$ and $Pt(II)$ are diamagnetic and square planar.
$(III) \ [Ni(CN)_4]^{4-}$ ion and $[Ni(CO)_4]$ are diamagnetic tetrahedral and square planar respectively.
$(IV) \ Ni^{2+}$ ion does not form inner orbital octahedral complexes.

Among the following,the square planar geometry is exhibited by:

For which of the following $d^n$ configurations of octahedral complexes,can they $NOT$ exist in both high spin and low spin forms?
$(I)$ $d^3$,$(II)$ $d^5$,$(III)$ $d^6$,$(IV)$ $d^8$

Match List – $I$ with List – $II$:
List - $I$ (Complex)List – $II$ (Geometry)
$(a)$ $[Co(NH_3)_6]^{3+}$$(i)$ Trigonal bipyramidal
$(b)$ $[NiCl_4]^{2-}$(ii) Octahedral
$(c)$ $[Ni(CN)_4]^{2-}$(iii) Tetrahedral
$(d)$ $[Fe(CO)_5]$(iv) Square planar

Choose the correct answer from the options given below.

Assertion : $[FeF_6]^{3-}$ is a low spin complex.
Reason : Low spin complexes have a lesser number of unpaired electrons.

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