Consider the following complexes:[CoCl(NH_3)_ | vedclass

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(B) The energy of the absorbed light is directly proportional to the crystal field splitting energy $(\Delta_o)$,which depends on the strength of the

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$D < A < C < B$

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(B) The energy of the absorbed light is directly proportional to the crystal field splitting energy $(\Delta_o)$,which depends on the strength of the ligands and the oxidation state of the metal ion.Energy $\propto$ Wavenumber $(\bar{v})$.$1$. For $D$ $([Cu(H_2O)_4]^{2+})$: $Cu^{2+}$ is a $3d^9$ system with weak field ligands $(H_2O)$,resulting in the lowest splitting energy.$2$. For $C$ $([Co(NH_3)_5(H_2O)]^{3+})$: $Co^{3+}$ is a $3d^6$ system. The ligands are $NH_3$ and $H_2O$. The splitting is higher than $D$.$3$. For $A$ $([CoCl(NH_3)_5]^{2+})$: $Co^{3+}$ with $NH_3$ and $Cl^-$. $Cl^-$ is a weaker ligand than $H_2O$,but the overall field strength of the complex is higher than $C$ due to the presence of five $NH_3$ ligands.$4$. For $B$ $([Co(CN)_6]^{3-})$: $Co^{3+}$ with $CN^-$ ligands. $CN^-$ is a strong field ligand,resulting in the largest splitting energy and thus the highest wavenumber.The order of increasing wavenumber is $D < C < A < B$. However,based on standard spectrochemical series and complex stability,the correct order is $D < A < C < B$.

Consider the following complexes:
$[CoCl(NH_3)_5]^{2+},$ $[Co(CN)_6]^{3-}$
$(A)$ $(B)$
$[Co(NH_3)_5(H_2O)]^{3+},$ $[Cu(H_2O)_4]^{2+}$
$(C)$ $(D)$
The correct order of $A, B, C,$ and $D$ in terms of the wavenumber of light absorbed is:

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Consider the following complexes:$[CoCl(NH_3)_5]^{2+},$ $[Co(CN)_6]^{3-}$$(A)$ $(B)$$[Co(NH_3)_5(H_2O)]^{3+},$ $[Cu(H_2O)_4]^{2+}$$(C)$ $(D)$The correct order of $A, B, C,$ and $D$ in terms of the wavenumber of light absorbed is: