Consider the following frequency distribution:
Class: $10-20$ $20-30$ $30-40$ $40-50$ $50-60$
Freq: $\alpha$ $110$ $54$ $30$ $\beta$

If the sum of all frequencies is $584$ and the median is $45$,then $|\alpha-\beta|$ is equal to $.....$

  • A
    $390$
  • B
    $164$
  • C
    $377$
  • D
    $113$

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Similar Questions

Let the mean and variance of $8$ numbers $x, y, 10, 12, 6, 12, 4, 8$ be $9$ and $9.25$ respectively. If $x > y$,then $3x - 2y$ is equal to $...........$.

Let $X = \{11, 12, 13, \ldots, 40, 41\}$ and $Y = \{61, 62, 63, \ldots, 90, 91\}$ be two sets of observations. If $\bar{x}$ and $\bar{y}$ are their respective means and $\sigma^2$ is the variance of all the observations in $X \cup Y$,then $|\bar{x} + \bar{y} - \sigma^2|$ is equal to $.................$.

Suppose that the mean and median of the non-negative numbers $21, 8, 17, a, 51, 103, b, 13, 67$ $(a > b)$ are $40$ and $21$, respectively. If the mean deviation about the median is $26$, then $2a$ is equal to:

The mean of a data set comprising $16$ observations is $16$. If one observation with value $16$ is deleted and three new observations with values $3, 4,$ and $5$ are added to the data,then the mean of the resultant data is:

Consider the given data with frequency distribution:
$x_{i} = \{3, 8, 11, 10, 5, 4\}$
$f_{i} = \{5, 2, 3, 2, 4, 4\}$
Match each entry in List-$I$ to the correct entries in List-$II$.
List-$I$List-$II$
$(P)$ The mean of the above data is$(1) 2.5$
$(Q)$ The median of the above data is$(2) 5$
$(R)$ The mean deviation about the mean of the above data is$(3) 6$
$(S)$ The mean deviation about the median of the above data is$(4) 2.7$
$(5) 2.4$

The correct option is :

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