Consider the following molecule $(X)$. The reaction of $(X)$ with $HBr$ gives the major product:

The chemical reaction is shown below:
$C_6H_5-CH_2-CH=CH_2 + HCl \rightarrow X$,$X$ is:

Addition of $HBr$ to propene in the presence of a peroxide takes place contrary to Markovnikov rule. This can be explained by the mechanism involving

Reaction of one molecule of $HBr$ with one molecule of $1,3-$butadiene at $40\,^{\circ}C$ gives predominantly

The addition of $HBr$ to $2-$pentene gives

How many propenyl radicals are possible from propene?