Consider the following organic reaction seque | vedclass

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Question

(C) The reaction sequence starting from propanoic acid $(CH_3CH_2COOH)$ is as follows:
$1$) Reaction with $NH_3/\Delta$ gives propanamide $(CH_3CH_2C

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Propanol

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(C) The reaction sequence starting from propanoic acid $(CH_3CH_2COOH)$ is as follows:
$1$) Reaction with $NH_3/\Delta$ gives propanamide $(CH_3CH_2CONH_2)$.
$2$) Hofmann bromamide degradation with $NaOH/Br_2$ converts propanamide to ethanamine $(CH_3CH_2NH_2)$.
$3$) Reaction with nitrous acid ($HNO_2$, from $NaNO_2/HCl$) at $0^\circ C$ converts ethanamine to ethanol $(CH_3CH_2OH)$.
$4$) The reaction of ethanol with benzenediazonium chloride $(C_6H_5N_2Cl)$ at $0^\circ C$ is not a standard textbook reaction for producing the given options. However, if the question intended to ask for the product after step $(iii)$, the product is ethanol. Given the options provided, there is no correct match for the final product. Assuming a potential error in the question's options or reagents, the most logical intermediate product is ethanol, which is not listed. Therefore, the question is flawed.

Consider the following organic reaction sequence. Choose the final product $(X)$ from the following (consider the major product in all intermediate reactions).

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