Consider the following reaction:
$C_6H_5COCl \xrightarrow{H_2, Pd-BaSO_4} 'A'$
The product $'A'$ is:

  • A
    $C_6H_5COCH_3$
  • B
    $C_6H_5Cl$
  • C
    $C_6H_5CHO$
  • D
    $C_6H_5OH$

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