Consider the following reaction:2 HSO_{4}^{-} | vedclass

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(C) The reaction describes the industrial preparation of hydrogen peroxide $(H_{2}O_{2})$ via the electrolysis of ammonium or potassium hydrogen sulfa

Vedclass · Accepted Answer

$90.2$

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(C) The reaction describes the industrial preparation of hydrogen peroxide $(H_{2}O_{2})$ via the electrolysis of ammonium or potassium hydrogen sulfate.The overall reaction is:$2 HSO_{4}^{-}(aq)$ $\xrightarrow[	ext{(2) Hydrolysis}]{	ext{(1) Electrolysis}} 2 HSO_{4}^{-}(aq) + 2 H^{+}(aq) + H_{2}O_{2}(aq)$Thus,product $A$ is hydrogen peroxide $(H_{2}O_{2})$.In the solid phase at $110 \ K$,the dihedral angle of $H_{2}O_{2}$ is $90.2^{\circ}$ due to the open book structure,whereas in the gas phase,it is $111.5^{\circ}$.

Consider the following reaction:
$2 HSO_{4}^{-}(aq)$ $\xrightarrow[\text{(2) Hydrolysis}]{\text{(1) Electrolysis}} H_{2}S_{2}O_{8}(aq)$ $\xrightarrow{\text{Hydrolysis}} 2 HSO_{4}^{-}(aq) + 2 H^{+}(aq) + A(aq)$
The dihedral angle in product $A$ in its solid phase at $110 \ K$ is ....$^{\circ}$

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Consider the following reaction:$2 HSO_{4}^{-}(aq)$ $\xrightarrow[\text{(2) Hydrolysis}]{\text{(1) Electrolysis}} H_{2}S_{2}O_{8}(aq)$ $\xrightarrow{\text{Hydrolysis}} 2 HSO_{4}^{-}(aq) + 2 H^{+}(aq) + A(aq)$The dihedral angle in product $A$ in its solid phase at $110 \ K$ is ....$^{\circ}$