(A) The molecular geometry of $BCl_3$ is trigonal planar because boron is $sp^2$ hybridized with three bond pairs and no lone pairs.In the adduct $BCl

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

trigonal planar and tetrahedral

(A) The molecular geometry of $BCl_3$ is trigonal planar because boron is $sp^2$ hybridized with three bond pairs and no lone pairs.In the adduct $BCl_3 \cdot NH_3$,the boron atom forms a coordinate bond with the nitrogen atom of $NH_3$.After the formation of the coordinate bond,the boron atom is surrounded by four atoms (three $Cl$ and one $N$),resulting in $sp^3$ hybridization.Therefore,the geometry of $BCl_3 \cdot NH_3$ is tetrahedral.

Class 11 Chemistry Chemical Bonding and Molecular Structure Hybridisation

Difficult

Consider the following reaction $BCl_3 + NH_3 \longrightarrow BCl_3 \cdot NH_3$. The geometries of $BCl_3$ and $BCl_3 \cdot NH_3$ respectively are

AP EAMCET 2021 All AP EAMCET

A
trigonal planar and tetrahedral
B
tetrahedral and square planar
C
tetrahedral and trigonal bipyramidal
D
square planar and trigonal pyramidal

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Chemistry Questions

Chapter

Chemical Bonding and Molecular Structure

Subtopic

Hybridisation

Previous Year

AP EAMCET 2021 Paper All AP EAMCET years →

Among the following compounds,the one that is polar and has a central atom with $sp^2$ hybridization is:

MediumIIT 1997

View Solution

Describe the change in hybridization (if any) of the $Al$ atom in the following reaction:
$AlCl_3 + Cl^{-} \to AlCl_4^-$

Medium

View Solution

Consider $PF_{5}$,$BrF_{5}$,$PCl_{3}$,$SF_{6}$,$[ICl_{4}]^{-}$,$ClF_{3}$ and $IF_{5}$.
Amongst the above molecule$(s)$/ion$(s)$,the number of molecule$(s)$/ion$(s)$ having $sp^{3}d^{2}$ hybridisation is $........$

DifficultJEE MAIN 2022

View Solution

Describe the change in hybridisation (if any) of the $Al$ atom in the following reaction.
$AlCl_{3} + Cl^{-} \longrightarrow AlCl_{4}^{-}$

Medium

View Solution

Hybrid state of Aluminium in acidified aqueous solution of $AlCl_3$ is

Difficult

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

Consider the following reaction $BCl_3 + NH_3 \longrightarrow BCl_3 \cdot NH_3$. The geometries of $BCl_3$ and $BCl_3 \cdot NH_3$ respectively are

Similar Questions

Among the following compounds,the one that is polar and has a central atom with $sp^2$ hybridization is:

Describe the change in hybridization (if any) of the $Al$ atom in the following reaction:$AlCl_3 + Cl^{-} \to AlCl_4^-$

Consider $PF_{5}$,$BrF_{5}$,$PCl_{3}$,$SF_{6}$,$[ICl_{4}]^{-}$,$ClF_{3}$ and $IF_{5}$.Amongst the above molecule$(s)$/ion$(s)$,the number of molecule$(s)$/ion$(s)$ having $sp^{3}d^{2}$ hybridisation is $........$

Describe the change in hybridisation (if any) of the $Al$ atom in the following reaction.$AlCl_{3} + Cl^{-} \longrightarrow AlCl_{4}^{-}$

Hybrid state of Aluminium in acidified aqueous solution of $AlCl_3$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Describe the change in hybridization (if any) of the $Al$ atom in the following reaction:
$AlCl_3 + Cl^{-} \to AlCl_4^-$

Consider $PF_{5}$,$BrF_{5}$,$PCl_{3}$,$SF_{6}$,$[ICl_{4}]^{-}$,$ClF_{3}$ and $IF_{5}$.
Amongst the above molecule$(s)$/ion$(s)$,the number of molecule$(s)$/ion$(s)$ having $sp^{3}d^{2}$ hybridisation is $........$

Describe the change in hybridisation (if any) of the $Al$ atom in the following reaction.
$AlCl_{3} + Cl^{-} \longrightarrow AlCl_{4}^{-}$