Consider the following reaction sequence:text | vedclass

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(D) $1$. Ozonolysis of $	ext{but-2-ene}$ gives acetaldehyde $(CH_3CHO)$ as $X$.$2$. Reaction of $X$ $(CH_3CHO)$ with $CH_3MgBr$ followed by hydrolysi

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$I$ & $III$ only

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(D) $1$. Ozonolysis of $	ext{but-2-ene}$ gives acetaldehyde $(CH_3CHO)$ as $X$.$2$. Reaction of $X$ $(CH_3CHO)$ with $CH_3MgBr$ followed by hydrolysis gives propan$-2-$ol $(CH_3CH(OH)CH_3)$ as $Y$.$3$. Dehydrogenation of $Y$ (a secondary alcohol) with $Cu$ at $573 \ K$ gives acetone $(CH_3COCH_3)$ as $Z$.$4$. $Z$ is acetone,which is a methyl ketone. It gives a positive iodoform test (yellow precipitate with $I_2$ and $NaOH$),so statement $I$ is correct.$5$. Acetone does not have $\alpha$-hydrogens that can lead to Cannizzaro reaction,so it does not undergo disproportionation with concentrated $NaOH$,making $II$ incorrect.$6$. Acetone undergoes Wolff-Kishner reduction to form propane,so statement $III$ is correct.$7$. Acetone is a ketone and does not reduce Fehling's reagent,so statement $IV$ is incorrect.Therefore,statements $I$ and $III$ are correct.

Similar Questions

Consider the reaction sequence and identify $'C'$.
$A + B \xrightarrow{dil \ NaOH / \Delta} C$
(The reaction sequence is: $3,3-\text{dimethylbut-1-ene} \xrightarrow[(ii) Zn/H_2O]{(i) O_3} A + B$)

Consider the following reaction sequence:
$4\text{-aminobenzonitrile}$ $\xrightarrow[(ii) H_2O]{(i) AlH(i-Bu)_2} 'A'$ $\xrightarrow[dil. NaOH, \Delta]{CH_3CHO} B$
The product $B$ is?

Reactant $(A)$ is:

$OHC-CH_2-CH_2-CH_2-CH_2-CHO \xrightarrow{OH^{-} / \Delta} \text{Product } (A) \text{ is:}$

One mole of an organic compound requires $0.5$ mole of oxygen to produce an acid. The compound may be

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