Consider the following reaction:CH_3-CH_2-CH( | vedclass

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(D) The reaction is a dehydrohalogenation of $2$-bromobutane using alcoholic $KOH$,which follows the $E2$ mechanism.According to Saytzeff's rule,the m

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$b, d$

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(D) The reaction is a dehydrohalogenation of $2$-bromobutane using alcoholic $KOH$,which follows the $E2$ mechanism.According to Saytzeff's rule,the major product in dehydrohalogenation is the more substituted alkene.Product $I$ is $but-1-ene$ (monosubstituted),and product $II$ is $but-2-ene$ (disubstituted).Since $but-2-ene$ $(II)$ is more substituted,it is more stable and is the major product.Therefore,statement $b$ is correct ($II$ is the major product) and statement $d$ is correct ($II$ is more stable because it is more substituted).Thus,the correct option is $b, d$.

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