Consider the following reactions at 1000,^oC: | vedclass

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(B) To determine if $ZnO$ can be reduced by $C$,we consider the coupled reaction:$Zn_{(s)} + \frac{1}{2}O_{2(g)} \rightarrow ZnO_{(s)}$; $\Delta G^o =

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$ZnO$ can be reduced to $Zn$ by $C$

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(B) To determine if $ZnO$ can be reduced by $C$,we consider the coupled reaction:$Zn_{(s)} + \frac{1}{2}O_{2(g)} \rightarrow ZnO_{(s)}$; $\Delta G^o = -360\,kJ\,mol^{-1}$$C_{(s)} + \frac{1}{2}O_{2(g)} \rightarrow CO_{(g)}$; $\Delta G^o = -460\,kJ\,mol^{-1}$Subtracting reaction $(I)$ from reaction $(II)$:$C_{(s)} + ZnO_{(s)} \rightarrow Zn_{(s)} + CO_{(g)}$The standard Gibbs free energy change for this reaction is:$\Delta G^o_{total} = \Delta G^o_{(II)} - \Delta G^o_{(I)} = -460 - (-360) = -100\,kJ\,mol^{-1}$Since $\Delta G^o_{total} Therefore,$ZnO$ can be reduced to $Zn$ by $C$.

Consider the following reactions at $1000\,^oC$:
$(I)$ $Zn_{(s)} + \frac{1}{2}O_{2(g)} \rightarrow ZnO_{(s)}; \Delta G^o = -360\,kJ\,mol^{-1}$
$(II)$ $C_{(s)} + \frac{1}{2}O_{2(g)} \rightarrow CO_{(g)}; \Delta G^o = -460\,kJ\,mol^{-1}$
Choose the correct statement at $1000\,^oC$.

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Consider the following reactions at $1000\,^oC$:$(I)$ $Zn_{(s)} + \frac{1}{2}O_{2(g)} \rightarrow ZnO_{(s)}; \Delta G^o = -360\,kJ\,mol^{-1}$$(II)$ $C_{(s)} + \frac{1}{2}O_{2(g)} \rightarrow CO_{(g)}; \Delta G^o = -460\,kJ\,mol^{-1}$Choose the correct statement at $1000\,^oC$.