Consider the following reactions:PCl_{3} + 3H | vedclass

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(B) The hydrolysis of $PCl_{3}$ proceeds as follows:$PCl_{3} + 3H_{2}O \longrightarrow H_{3}PO_{3} (A) + 3HCl$However,the question implies a stepwise

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$2$

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(B) The hydrolysis of $PCl_{3}$ proceeds as follows:$PCl_{3} + 3H_{2}O \longrightarrow H_{3}PO_{3} (A) + 3HCl$However,the question implies a stepwise hydrolysis where $A$ is an intermediate like $PCl_{2}(OH)$ or $PCl(OH)_{2}$.Upon further hydrolysis,$A$ converts to $B$,which is phosphorous acid $(H_{3}PO_{3})$.The structure of $H_{3}PO_{3}$ is $H-P(=O)(OH)_{2}$.In $H_{3}PO_{3}$,only the two hydrogen atoms attached to oxygen atoms are ionisable as protons $(H^{+})$.The hydrogen atom directly attached to the phosphorus atom is not ionisable.Therefore,the number of ionisable protons in $B$ is $2$.

Consider the following reactions:
$PCl_{3} + 3H_{2}O \longrightarrow A + 3HCl$
$A + H_{2}O \longrightarrow B + HCl$
Identify the number of ionisable protons present in the product $B$.

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Consider the following reactions:$PCl_{3} + 3H_{2}O \longrightarrow A + 3HCl$$A + H_{2}O \longrightarrow B + HCl$Identify the number of ionisable protons present in the product $B$.