Consider the following reversible reaction at | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction is endothermic $(\Delta H > 0)$,so according to Le Chatelier's principle,increasing the temperature will shift the equilibrium in the

Vedclass · Accepted Answer

Increasing temperature and decreasing pressure

Vedclass · Answer

(C) The reaction is endothermic $(\Delta H > 0)$,so according to Le Chatelier's principle,increasing the temperature will shift the equilibrium in the forward direction.The change in the number of moles of gaseous products is $\Delta n_g = (2+1) - 2 = +1$.Since $\Delta n_g > 0$,decreasing the pressure will shift the equilibrium in the direction of more moles of gas,which is the forward direction.Therefore,increasing the temperature and decreasing the pressure will lead to the maximum decomposition of $H_2O_{(g)}$.

Consider the following reversible reaction at equilibrium,$2H_2O_{(g)} \rightleftharpoons 2H_{2(g)} + O_{2(g)}$; $\Delta H = 241.7 \ kJ$. Which one of the following changes in conditions will lead to maximum decomposition of $H_2O_{(g)}$?

Similar Questions

State Le Chatelier's Principle.

In which of the following reactions will a change in pressure not affect the rate of reaction?

In which of the following equilibria does a change in the volume of the system not alter the number of moles?

Which reaction is not affected by a change in pressure?

According to Le Chatelier's principle,if a gaseous mixture is compressed,what will be the effect on the equilibrium of the following reaction: $N_2O_{4(g)} \rightleftharpoons 2NO_{2(g)}$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module