Consider the following sequence of reactions. | vedclass

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(B) Step $1$: Ozonolysis of $C_2H_4$ $(CH_2=CH_2)$ gives formaldehyde $(HCHO)$ as $P$.Step $2$: Reaction of $HCHO$ with $CH_3MgBr$ followed by hydroly

Vedclass · Accepted Answer

It undergoes Cannizzaro reaction

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(B) Step $1$: Ozonolysis of $C_2H_4$ $(CH_2=CH_2)$ gives formaldehyde $(HCHO)$ as $P$.Step $2$: Reaction of $HCHO$ with $CH_3MgBr$ followed by hydrolysis gives ethanol $(CH_3CH_2OH)$ as $Q$.Step $3$: Oxidation of ethanol $(CH_3CH_2OH)$ with $PCC$ gives acetaldehyde $(CH_3CHO)$ as $R$.$R$ is $CH_3CHO$,which contains $\alpha$-hydrogens. Therefore,it cannot undergo the Cannizzaro reaction. It gives a positive Tollen's test,iodoform test,and undergoes aldol condensation. Thus,the incorrect statement is that it undergoes the Cannizzaro reaction.

Column $I$	Column $II$
$A$. $C_6H_5CHO$	$p$. gives precipitate with $2, 4-$dinitrophenylhydrazine
$B$. $CH_3C \equiv CH$	$q$. gives precipitate with $AgNO_3$
$C$. $CN^{-}$	$r$. is a nucleophile
$D$. $I^{-}$	$s$. is involved in cyanohydrin formation

Consider the following sequence of reactions. The incorrect statement about $R$ is:

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