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(D) The reaction sequence describes the qualitative analysis of Group $V$ cations $(Ca^{2+}, Sr^{2+}, Ba^{2+})$.$1$. When $NH_4Cl(s)$ and $(NH_4)_2CO_

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$Ba^{2+}(aq.)$

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(D) The reaction sequence describes the qualitative analysis of Group $V$ cations $(Ca^{2+}, Sr^{2+}, Ba^{2+})$.$1$. When $NH_4Cl(s)$ and $(NH_4)_2CO_3$ solution are added,$Ca^{2+}, Sr^{2+},$ and $Ba^{2+}$ form carbonate precipitates $(Q = CaCO_3, SrCO_3, BaCO_3)$. $Mg^{2+}$ does not precipitate in the presence of $NH_4Cl$.$2$. These carbonate precipitates are dissolved in $CH_3COOH$ to form their respective acetates.$3$. Upon adding $(NH_4)_2C_2O_4$,$Ca^{2+}$ and $Sr^{2+}$ form oxalate precipitates $(R = CaC_2O_4, SrC_2O_4)$,whereas $Ba^{2+}$ remains in the filtrate because $BaC_2O_4$ is relatively more soluble.Therefore,$Ba^{2+}$ forms precipitate $Q$ but does not form precipitate $R$ under these conditions.

Consider the following sequence of reactions:
$M^{2+}(aq.)$ $\xrightarrow{NH_4Cl(s) + (NH_4)_2CO_3 \, sol.} Q \downarrow$ $\xrightarrow[\text{Followed by addition of } (NH_4)_2C_2O_4]{CH_3COOH} R \downarrow$
Which of the following cations can form precipitate $Q$ but does not form precipitate $R$?

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Consider the following sequence of reactions:$M^{2+}(aq.)$ $\xrightarrow{NH_4Cl(s) + (NH_4)_2CO_3 \, sol.} Q \downarrow$ $\xrightarrow[\text{Followed by addition of } (NH_4)_2C_2O_4]{CH_3COOH} R \downarrow$Which of the following cations can form precipitate $Q$ but does not form precipitate $R$?