Consider the following statements. Acetopheno | vedclass

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(C) $1$. Oxidation of $1$-phenylethanol $(C_6H_5CH(OH)CH_3)$ using an oxidizing agent like $KMnO_4$ or $CrO_3$ yields acetophenone $(C_6H_5COCH_3)$.$2

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$1$ and $3$

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(C) $1$. Oxidation of $1$-phenylethanol $(C_6H_5CH(OH)CH_3)$ using an oxidizing agent like $KMnO_4$ or $CrO_3$ yields acetophenone $(C_6H_5COCH_3)$.$2$. Reaction of benzaldehyde with methyl magnesium bromide $(CH_3MgBr)$ yields $1$-phenylethanol,not acetophenone.$3$. Friedel-Crafts acylation of benzene with acetyl chloride $(CH_3COCl)$ in the presence of anhydrous $AlCl_3$ yields acetophenone $(C_6H_5COCH_3)$.$4$. Dry distillation of calcium benzoate yields benzophenone $(C_6H_5COC_6H_5)$,not acetophenone.Therefore,statements $1$ and $3$ are correct.

Consider the following statements. Acetophenone can be prepared by:
$1$. Oxidation of $1$-phenylethanol
$2$. Reaction of benzaldehyde with methyl magnesium bromide
$3$. Friedel-Crafts reaction of benzene with acetyl chloride
$4$. Distillation of calcium benzoate

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Consider the following statements. Acetophenone can be prepared by:$1$. Oxidation of $1$-phenylethanol$2$. Reaction of benzaldehyde with methyl magnesium bromide$3$. Friedel-Crafts reaction of benzene with acetyl chloride$4$. Distillation of calcium benzoate