Consider the following statements about the h | vedclass

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(C) Statement $(I)$ is incorrect because the reaction between $NaH$ and $H_2O$ releases hydrogen gas,not oxygen gas: $NaH + H_2O \rightarrow NaOH + H_

Vedclass · Accepted Answer

$II$ & $IV$ only

Vedclass · Answer

(C) Statement $(I)$ is incorrect because the reaction between $NaH$ and $H_2O$ releases hydrogen gas,not oxygen gas: $NaH + H_2O \rightarrow NaOH + H_2 \uparrow$. Statement $(II)$ is correct; $CH_4$ and $SiH_4$ have the required number of electrons to form normal covalent bonds,making them electron-precise hydrides. Statement $(III)$ is incorrect; $NH_3$ and $H_2O$ are electron-rich hydrides because they possess lone pairs of electrons on the central atom. Statement $(IV)$ is correct; hydrides of $Be$ and $Mg$ ($BeH_2$ and $MgH_2$) are electron-deficient and exist in polymeric structures. Thus,statements $(II)$ and $(IV)$ are correct.

Similar Questions

Which of the following statements is not true for hydrogen:
$1)$ It exists as a diatomic molecule.
$2)$ It has one electron in the outermost shell.
$3)$ It can lose an electron to form a cation which can freely exist.
$4)$ It cannot form ionic compounds.

Assertion : Hydrogen combines with other elements by losing,gaining or sharing of electrons.
Reason : Hydrogen forms electrovalent and covalent bonds with other elements.

What is Carbogen?

Which of the following is true for the industrial production of hydrogen from water gas $(CO + H_2)$?

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