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(A) The deviation produced by a prism is given by $\delta = i + e - A$.At the condition of minimum deviation $(\delta_{	ext{min}})$,the angle of inci

Vedclass · Accepted Answer

$A, C$ and $D$ Only

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(A) The deviation produced by a prism is given by $\delta = i + e - A$.At the condition of minimum deviation $(\delta_{	ext{min}})$,the angle of incidence equals the angle of emergence $(i = e)$.Under this condition,the refracted ray inside the prism is parallel to the base of the prism.Statement $(A)$ is correct because the ray inside is parallel to the base.Statement $(C)$ is correct because $i = e$ at minimum deviation.Statement $(D)$ is correct because for any deviation $\delta > \delta_{	ext{min}}$,there exist two angles of incidence $i_1$ and $i_2$ such that $i_1 = e$ and $i_2 = i$,resulting in the same deviation.Statement $(B)$ is incorrect because a larger prism angle $A$ generally leads to a larger angle of minimum deviation.Statement $(E)$ is incorrect because at minimum deviation,$r_1 = r_2 = A/2$,so the angle of refraction is half the prism angle,not double.Therefore,the correct statements are $(A), (C),$ and $(D)$.

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