Consider the following statements:A. NF_3 mol | vedclass

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(D) . $NF_3$ has a trigonal pyramidal shape due to the presence of one lone pair on the $N$ atom.$B$. The bond order of $N_2$ is $3$ and $O_2$ is $2$.

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$B$ and $C$ are correct

Vedclass · Answer

(D) . $NF_3$ has a trigonal pyramidal shape due to the presence of one lone pair on the $N$ atom.$B$. The bond order of $N_2$ is $3$ and $O_2$ is $2$. Higher bond order implies shorter bond length,so $N_2$ has a shorter bond length than $O_2$. Statement $B$ is correct.$C$. Isoelectronic species (e.g.,$N_2$ and $CO$) have identical bond orders. Statement $C$ is correct.$D$. The dipole moment of $H_2O$ $(1.85 \ D)$ is higher than that of $H_2S$ $(0.95 \ D)$ due to the higher electronegativity of oxygen compared to sulfur. Statement $D$ is incorrect.Therefore,statements $B$ and $C$ are correct.

List-$I$	List-$II$
$(P). \ IF_7$	$(a). \ \text{Planar} \ \& \ \text{Polar}$
$(Q). \ SO_2$	$(b). \ \text{Non-planar} \ \& \ \text{Polar}$
$(R). \ SF_4$	$(c). \ \text{Planar} \ \& \ \text{Non-polar}$
$(S). \ CS_2$	$(d). \ \text{Non-planar} \ \& \ \text{Non-polar}$

Similar Questions

$NH_2^-$,$NH_3$ and $NH_4^+$ do not show similarity in the following:

Which of these represents the incorrect order of the mentioned property?

What is the formal charge on the $N$ atom in the $NH_4^{+}$ ion?

Match List-$I$ with List-$II$:

List-$I$ List-$II$

$(P). \ IF_7$ $(a). \ \text{Planar} \ \& \ \text{Polar}$

$(Q). \ SO_2$ $(b). \ \text{Non-planar} \ \& \ \text{Polar}$

$(R). \ SF_4$ $(c). \ \text{Planar} \ \& \ \text{Non-polar}$

$(S). \ CS_2$ $(d). \ \text{Non-planar} \ \& \ \text{Non-polar}$

The type of molecular forces of attraction present in the following compound is

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