Consider the following transformation 2 CuX_ | vedclass

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(C) The reaction $2 \ CuX_2 \rightarrow Cu_2X_2 + X_2$ represents the reduction of $Cu^{2+}$ to $Cu^{+}$ by the halide or pseudohalide ion $X^{-}$.Thi

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$CN^{-}, I^{-}$

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(C) The reaction $2 \ CuX_2 \rightarrow Cu_2X_2 + X_2$ represents the reduction of $Cu^{2+}$ to $Cu^{+}$ by the halide or pseudohalide ion $X^{-}$.This reaction occurs spontaneously at room temperature when $X^{-}$ is a strong reducing agent,such as $I^{-}$ or $CN^{-}$.In the case of $Cl^{-}$ and $Br^{-}$,the reduction of $Cu^{2+}$ to $Cu^{+}$ is not strong enough to occur at room temperature,and $F^{-}$ is not a reducing agent at all.

Consider the following transformation $2 \ CuX_2 \xrightarrow[\text{Room}]{\text{temp.}} Cu_2X_2 + X_2 \uparrow$. Then $X^{-}$ can be:

Similar Questions

Consider the following transformation:
$2CuX_2 \xrightarrow{\text{Room temperature}} 2CuX + X_2 \uparrow$
Then $X^-$ can be:

Transition metal with low oxidation number will act as

How many statements are incorrect?
$(a)$ $Mn^{+3}$ and $Co^{+3}$ are strong oxidising agents.
$(b)$ $Ti^{+2}$,$V^{+2}$ and $Cr^{+2}$ are strong reducing agents.
$(c)$ $CrO_3$ is acidic in nature.
$(d)$ $E^{\circ}_{M^{+3}/M^{+2}} = -ve$ for $Fe$.

Identify the correct order of oxidizing power.

When $SO_{2}$ is passed through acidified $K_{2}Cr_{2}O_{7}$ solution:

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