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(D) $1$. Compound $P$ $(C_9H_{12})$ on hydrogenation with $Pt/H_2$ gives propylcyclohexane,indicating $P$ has a cyclohexyl ring and a propyl chain wit

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$A, B$

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(D) $1$. Compound $P$ $(C_9H_{12})$ on hydrogenation with $Pt/H_2$ gives propylcyclohexane,indicating $P$ has a cyclohexyl ring and a propyl chain with a triple bond.$2$. The reaction with $NaNH_2$ followed by $C_6H_5COCH_3$ and $H_3O^+/\Delta$ confirms $P$ is a terminal alkyne,specifically $3-$cyclohexylprop$-1-$yne.$3$. $X$ is a reagent that partially reduces the alkyne to an alkene,which is $Pd-C/	ext{quinoline}/H_2$ (Lindlar's catalyst).$4$. Oxidation of the resulting alkene with $KMnO_4/H_2SO_4/\Delta$ yields the optically active acid $Q$.$5$. Thus,$P$ is $3-$cyclohexylprop$-1-$yne (Option $A$) and $X$ is $Pd-C/	ext{quinoline}/H_2$ (Option $B$).$6$. Therefore,the correct options are $A$ and $B$.

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