Consider the following volume-temperature (V- | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For an ideal gas,the change in enthalpy $(\Delta H)$ depends only on the initial and final temperatures,as enthalpy is a state function.Given:Numb

Vedclass · Accepted Answer

$8120$

Vedclass · Answer

(D) For an ideal gas,the change in enthalpy $(\Delta H)$ depends only on the initial and final temperatures,as enthalpy is a state function.Given:Number of moles,$n = 5 \ mol$Initial temperature,$T_1 = 335 \ K$Final temperature,$T_2 = 415 \ K$Molar heat capacity at constant volume,$C_{v,m} = 12 \ J \ K^{-1} \ mol^{-1}$Gas constant,$R = 8.3 \ J \ K^{-1} \ mol^{-1}$Step $1$: Calculate the molar heat capacity at constant pressure $(C_{p,m})$.$C_{p,m} = C_{v,m} + R = 12 + 8.3 = 20.3 \ J \ K^{-1} \ mol^{-1}$Step $2$: Calculate the total change in enthalpy $(\Delta H)$.$\Delta H = n 	imes C_{p,m} 	imes (T_2 - T_1)$$\Delta H = 5 	imes 20.3 	imes (415 - 335)$$\Delta H = 5 	imes 20.3 	imes 80$$\Delta H = 8120 \ J$

$A$. Steam engine	$I$. Magnetic confinement of plasma
$B$. Electron microscope	$II$. Laws of thermodynamics
$C$. Non-reflecting coatings	$III$. Wave nature of electrons
$D$. Tokamak	$IV$. Interference of light

Similar Questions

One mole of an ideal gas goes from an initial state $A$ to a final state $B$ via two processes: It first undergoes isothermal expansion from volume $V$ to $3V$ and then its volume is reduced from $3V$ to $V$ at constant pressure. The correct $P-V$ diagram representing the two processes is:

$A$ cyclic process for $1 \, \text{mole}$ of an ideal gas is shown in the $V-T$ diagram. Find the work done in processes $AB$, $BC$, and $CA$ respectively.

The relation between the efficiency $\eta$ of a heat engine and the coefficient of performance $\alpha$ of a refrigerator is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module