Consider the given plot of enthalpy of the fo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) From the graph: Enthalpy of $(A+B) = 5\,kJ\,mol^{-1}$. Enthalpy of $D = 10\,kJ\,mol^{-1}$. Enthalpy of $C = 0\,kJ\,mol^{-1}$. Activation energy fo

Vedclass · Accepted Answer

Activation enthalpy to form $C$ is $5\,kJ\,mol^{-1}$ less than that to form $D$.

Vedclass · Answer

(D) From the graph: Enthalpy of $(A+B) = 5\,kJ\,mol^{-1}$. Enthalpy of $D = 10\,kJ\,mol^{-1}$. Enthalpy of $C = 0\,kJ\,mol^{-1}$. Activation energy for $(A+B 	o D) = 15 - 5 = 10\,kJ\,mol^{-1}$. Activation energy for $(A+B 	o C) = 20 - 5 = 15\,kJ\,mol^{-1}$. Activation energy for $(C 	o A+B) = 20 - 0 = 20\,kJ\,mol^{-1}$. Activation energy for $(D 	o A+B) = 15 - 10 = 5\,kJ\,mol^{-1}$. Comparing the activation energies,the formation of $(A+B)$ from $C$ has the highest activation energy $(20\,kJ\,mol^{-1})$. $C$ is the most stable product (lowest enthalpy). $D$ is formed faster (lower activation energy),so it is the kinetically stable product. Activation enthalpy to form $C$ $(15\,kJ\,mol^{-1})$ is $5\,kJ\,mol^{-1}$ more than that to form $D$ $(10\,kJ\,mol^{-1})$. Therefore,statement $D$ is incorrect.

Consider the given plot of enthalpy of the following reaction between $A$ and $B$: $A + B \to C + D$. Identify the incorrect statement.

Similar Questions

$A$ catalyst:

Which among the following equations represents the Arrhenius equation?

According to the Arrhenius equation,the slope of the $\log k$ vs. $\frac{1}{T}$ plot is . . . . . . .

The reaction rate at a given temperature becomes slower,then

Vedclass Test Series

Exam Paper Generator

Online Exam Module