Consider the given plots of vapour pressure ( | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The freezing point of a substance is the temperature at which the vapour pressure of the substance in its liquid phase is equal to its vapour pres

Vedclass · Accepted Answer

Vedclass · Answer

(D) The freezing point of a substance is the temperature at which the vapour pressure of the substance in its liquid phase is equal to its vapour pressure in the solid phase. When a non-volatile solute is added to a solvent,the vapour pressure of the solution decreases. The freezing point of the solution $(T_f)$ is lower than the freezing point of the pure solvent $(T_f^\circ)$. The graphical representation of depression in freezing point involves the intersection of the vapour pressure curve of the liquid solvent with the vapour pressure curve of the solid solvent (frozen solvent) to determine $T_f^\circ$,and the intersection of the vapour pressure curve of the solution with the vapour pressure curve of the solid solvent to determine $T_f$. Option $D$ correctly depicts the curves for the liquid solvent,the solution,and the frozen solvent,showing the depression in freezing point $\Delta T_f = T_f^\circ - T_f$.

Consider the given plots of vapour pressure $(VP)$ vs temperature $(T / K)$. Which amongst the following options is the correct graphical representation showing $\Delta T_f$,the depression in the freezing point of the solvent in a solution?

Similar Questions

Which of the following $0.10 \ m$ aqueous solutions will have the lowest freezing point?

What happens to the freezing point of benzene when a small quantity of naphthalene is added to it?

Give the unit of $K_f$.

Arrange the following solutions in order of decreasing freezing points:
$(a) \ 0.075 \ M \ CuSO_4$ $(b) \ 0.060 \ M \ (NH_4)_2SO_4$
$(c) \ 0.14 \ M \ urea$ $(d) \ 0.04 \ M \ MgCl_2$

$x$ moles of $CO(NH_2)_2$ are present in $1200 \ g$ of water. If the freezing point of the solution is $-4.02 \ ^oC$,calculate the value of $x$. Given $k_f \ (H_2O) = 1.86 \ K \ kg \ mol^{-1}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module