Consider the reaction, 3I^-_{(aq)} + S_2O_8^{ | vedclass

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(C) The rate of reaction is given by the expression:$	ext{Rate} = -\frac{1}{3} \frac{d[I^-]}{dt} = \frac{1}{2} \frac{d[SO_4^{2-}]}{dt}$Given that the

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$3.3 	imes 10^{-2} 	ext{ mol dm}^{-3} 	ext{s}^{-1}$

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(C) The rate of reaction is given by the expression:$	ext{Rate} = -\frac{1}{3} \frac{d[I^-]}{dt} = \frac{1}{2} \frac{d[SO_4^{2-}]}{dt}$Given that the rate of formation of $SO_4^{2-}$ is $\frac{d[SO_4^{2-}]}{dt} = 2.2 	imes 10^{-2} 	ext{ mol dm}^{-3} 	ext{s}^{-1}$.We need to find the rate of consumption of $I^-$, which is $-\frac{d[I^-]}{dt}$.From the expression: $-\frac{d[I^-]}{dt} = \frac{3}{2} 	imes \frac{d[SO_4^{2-}]}{dt}$$-\frac{d[I^-]}{dt} = \frac{3}{2} 	imes (2.2 	imes 10^{-2} 	ext{ mol dm}^{-3} 	ext{s}^{-1})$$-\frac{d[I^-]}{dt} = 3.3 	imes 10^{-2} 	ext{ mol dm}^{-3} 	ext{s}^{-1}$.

Consider the reaction, $3I^-_{(aq)} + S_2O_8^{2-} (aq) \rightarrow I_3^- (aq) + 2SO_4^{2-} (aq)$. If the rate of formation of $SO_4^{2-}$ at a particular time is $2.2 \times 10^{-2} \text{ mol dm}^{-3} \text{s}^{-1}$, calculate the rate of consumption of $I^-$.

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