Consider the reaction:KOH + O_3 to coloured s | vedclass

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(B) The reaction is: $2KOH + 2O_3 	o 2KO_3 + O_2 + H_2O$.Here,$(a)$ is $KO_3$ (potassium ozonide) and $(b)$ is $O_2$ (oxygen gas).$KO_3$ contains the

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$(b)$ does not react directly with $Xe$

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(B) The reaction is: $2KOH + 2O_3 	o 2KO_3 + O_2 + H_2O$.Here,$(a)$ is $KO_3$ (potassium ozonide) and $(b)$ is $O_2$ (oxygen gas).$KO_3$ contains the ozonide ion $(O_3^-)$,which has one unpaired electron,making it paramagnetic.$KO_3$ reacts with $HCl$ to produce $O_2$ gas: $2KO_3 + 2HCl 	o 2KCl + 2O_2 + H_2O$.$O_2$ does not react directly with $Xe$ under standard conditions.Therefore,the statement '$(b)$ does not react directly with $Xe$' is correct.

Consider the reaction:
$KOH + O_3 \to$ coloured solid $(a) +$ Gas $(b) + H_2O$
Select the $CORRECT$ statement.

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Consider the reaction:$KOH + O_3 \to$ coloured solid $(a) +$ Gas $(b) + H_2O$Select the $CORRECT$ statement.