(C) For the given system, let $a$ be the acceleration of the blocks and $T$ be the tension in the string.For mass $m_1$ moving horizontally: $T = m_1

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$\sqrt{\left(\frac{m_2}{m_1+m_2}\right) 2 g h}$

(C) For the given system, let $a$ be the acceleration of the blocks and $T$ be the tension in the string.For mass $m_1$ moving horizontally: $T = m_1 a$For mass $m_2$ moving vertically downwards: $m_2 g - T = m_2 a$Adding these two equations: $m_2 g = (m_1 + m_2) a$Therefore, the acceleration of the system is $a = \frac{m_2 g}{m_1 + m_2}$.Using the kinematic equation $v^2 = u^2 + 2ah$, where initial velocity $u = 0$ and displacement is $h$:$v^2 = 0 + 2 \left( \frac{m_2 g}{m_1 + m_2} \right) h$$v = \sqrt{\left( \frac{m_2}{m_1 + m_2} \right) 2 g h}$.

Class 11 Physics Newton's Laws of Motion and Friction Motion of Body (or Connected Bodies in horizontal or vertical) (by String or Contact)

Easy

Consider two masses $m_1$ and $m_2$ connected through a pulley as shown in the figure. Mass $m_2$ starts from rest at height $h$ and falls down. With what speed does it hit the ground? (Assume no friction and massless strings and pulleys.)

TS EAMCET 2021 All TS EAMCET

A
$\sqrt{\left(\frac{m_2}{m_1+m_2}\right) g h}$
B
$\sqrt{2 g h}$
C
$\sqrt{\left(\frac{m_2}{m_1+m_2}\right) 2 g h}$
D
$\sqrt{\left(\frac{m_1}{m_1+m_2}\right) 2 g h}$

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Newton's Laws of Motion and Friction

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Motion of Body (or Connected Bodies in horizontal or vertical) (by String or Contact)

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What is the minimum acceleration with which a person can slide down a rope,if the breaking strength of the rope is $\frac{2}{3}$ of the person's weight?

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$A$ mass $1\, kg$ is suspended by a thread. It is
$(i)$ lifted up with an acceleration $4.9\, m/s^2$
$(ii)$ lowered with an acceleration $4.9\, m/s^2$.
The ratio of the tensions is

MediumAIPMT 1998

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Two spheres $P$ and $Q$,each of mass $200 \text{ g}$,are attached to a string of length $1 \text{ m}$ as shown in the figure. The string and the spheres are then whirled in a horizontal circle about $O$ at a constant angular speed. The ratio of the tension in the string between $P$ and $Q$ to that between $P$ and $O$ is (where $P$ is at the mid-point of the line joining $O$ and $Q$).

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Two masses of $5\, kg$ and $3\, kg$ are suspended with the help of massless inextensible strings as shown in the figure. Calculate $T_1$ and $T_2$ when the whole system is moving upwards with an acceleration $a = 2\, m/s^2$ (use $g = 9.8\, m/s^2$).

Medium

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$A$ block $A$ of mass $7 \, kg$ is placed on a frictionless table. $A$ thread tied to it passes over a frictionless pulley and carries a body $B$ of mass $3 \, kg$ at the other end. The acceleration of the system is .......... $m \, s^{-2}$ (given $g = 10 \, m \, s^{-2}$).

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Consider two masses $m_1$ and $m_2$ connected through a pulley as shown in the figure. Mass $m_2$ starts from rest at height $h$ and falls down. With what speed does it hit the ground? (Assume no friction and massless strings and pulleys.)

Similar Questions

What is the minimum acceleration with which a person can slide down a rope,if the breaking strength of the rope is $\frac{2}{3}$ of the person's weight?

$A$ mass $1\, kg$ is suspended by a thread. It is$(i)$ lifted up with an acceleration $4.9\, m/s^2$$(ii)$ lowered with an acceleration $4.9\, m/s^2$.The ratio of the tensions is

Two masses of $5\, kg$ and $3\, kg$ are suspended with the help of massless inextensible strings as shown in the figure. Calculate $T_1$ and $T_2$ when the whole system is moving upwards with an acceleration $a = 2\, m/s^2$ (use $g = 9.8\, m/s^2$).

$A$ block $A$ of mass $7 \, kg$ is placed on a frictionless table. $A$ thread tied to it passes over a frictionless pulley and carries a body $B$ of mass $3 \, kg$ at the other end. The acceleration of the system is .......... $m \, s^{-2}$ (given $g = 10 \, m \, s^{-2}$).

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$A$ mass $1\, kg$ is suspended by a thread. It is
$(i)$ lifted up with an acceleration $4.9\, m/s^2$
$(ii)$ lowered with an acceleration $4.9\, m/s^2$.
The ratio of the tensions is