Considering the above reactions,the compound | vedclass

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Question

(A) $NaCN$ is an ionic compound,so it provides $CN^-$ ions in solution. The carbon atom is more nucleophilic than the nitrogen atom,leading to the for

Vedclass · Accepted Answer

$CH_3CH_2NC, CH_3CH_2CN$

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(A) $NaCN$ is an ionic compound,so it provides $CN^-$ ions in solution. The carbon atom is more nucleophilic than the nitrogen atom,leading to the formation of alkyl cyanide $(R-CN)$ as the major product.$AgCN$ is a covalent compound. The nitrogen atom has a lone pair of electrons available for nucleophilic attack,while the carbon atom is involved in a covalent bond with silver. This leads to the formation of alkyl isocyanide $(R-NC)$ as the major product.Therefore,for the reaction with $AgCN$,the product $A$ is $CH_3CH_2NC$ (ethyl isocyanide),and for the reaction with $NaCN$,the product $B$ is $CH_3CH_2CN$ (ethyl cyanide).

Column-$I$	Column-$II$
$(i)$ $R-Cl + NaI \xrightarrow{\text{dry acetone}} R-I + NaCl$	$(a)$ Swarts reaction
$(ii)$ $CH_3-Br + AgF \xrightarrow{\Delta} CH_3-F + AgBr$	$(b)$ Wurtz reaction
$(iii)$ $R-X + Mg$ $\xrightarrow{\text{dry ether}} R-Mg-X$ $\xrightarrow{H_2O} RH + Mg(OH)X$	$(c)$ Finkelstein reaction
	$(d)$ Grignard reaction

Considering the above reactions,the compound $A$ and compound $B$ respectively are:

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