Construct an equilateral $\Delta ABC$ in which $AB = BC = CA = 5 \, cm$. Write the steps of construction.

(N/A) Steps of construction:
$1$. Draw a line segment $AB = 5 \, cm$ using a ruler.
$2$. With $A$ as the center and radius $5 \, cm$,draw an arc above the line segment $AB$.
$3$. With $B$ as the center and radius $5 \, cm$,draw another arc intersecting the previous arc at point $C$.
$4$. Join $AC$ and $BC$.
$5$. Thus,$\Delta ABC$ is the required equilateral triangle with side length $5 \, cm$.