Construct an angle of the following measurement:
$22 \frac{1}{2}^{\circ}$

(N/A) Steps of construction:
$I.$ Draw a ray $\overrightarrow{OA}$.
$II.$ Construct $\angle AOB = 90^{\circ}$.
$III.$ Draw $OC$,the angle bisector of $\angle AOB$,such that $\angle AOC = \frac{1}{2} \angle AOB = \frac{1}{2}(90^{\circ}) = 45^{\circ}$.
$IV.$ Now,draw $OD$,the angle bisector of $\angle AOC$,such that $\angle AOD = \frac{1}{2} \angle AOC = \frac{1}{2}(45^{\circ}) = 22 \frac{1}{2}^{\circ}$.
Thus,$\angle AOD = 22 \frac{1}{2}^{\circ}$ is the required angle.